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I have regex like this:

^page/(?P<id>d+)-(?P<slug>[^.]+).html$

and an array:

$args = array(
    'id' => 5,
    'slug' => 'my-first-article'
);

I would like to have function:

my_function($regex, $args)

which will return this result:

page/5-my-first-article.html

How can this be achieved?

Something like https://docs.djangoproject.com/en/dev/ref/urlresolvers/#reverse

See Question&Answers more detail:os

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1 Answer

Interesting challenge, I coded something that works for this sample, note that you need PHP 5.3+ for this code to work:

$regex = '^page/(?P<id>d+)-(?P<slug>[.]+).html$';
$args = array(
    'id' => 5,
    'slug' => 'my-first-article'
);

$result = preg_replace_callback('#(?P<(w+)>[^)]+)#', function($m)use($args){
    if(array_key_exists($m[1], $args)){
        return $args[$m[1]];
    }
}, $regex);

$result = preg_replace(array('#^^|$$#', '#\\.#'), array('', '.'), $result); // To remove ^ and $ and replace . with .
echo $result;

Output: page/5-my-first-article.html

Online demo.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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