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I have been trying to get the answer for this question and after some R&D i have come up with the solution too

$begin = new DateTime('2014-11-01');
$end = new DateTime('2014-11-30');
$end = $end->modify('+1 day');
$interval = new DateInterval('P1D');
$daterange = new DatePeriod($begin, $interval, $end);

foreach ($daterange as $date) {
    $sunday = date('w', strtotime($date->format("Y-m-d")));
    if ($sunday == 0) {
        echo $date->format("Y-m-d") . "<br>";
    } else {
        echo'';
    }
}
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1 Answer

Try this way:

$begin  = new DateTime('2014-11-01');
$end    = new DateTime('2014-11-30');
while ($begin <= $end) // Loop will work begin to the end date 
{
    if($begin->format("D") == "Sun") //Check that the day is Sunday here
    {
        echo $begin->format("Y-m-d") . "<br>";
    }

    $begin->modify('+1 day');
}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
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