php generate random image from a directory

Question

I have to generate random image from a directory. I know which is simple like,

   $dire="images/";
   $images = glob($dire. '*.{jpg,jpeg,png,gif}', GLOB_BRACE);
   $randomImage = $images[array_rand($images)];
   <input type="image" src="<?=$randomImage;?>" alt="<?=$randomImage;?>" />

But I have to make sure that each image from that directory picked at least one time before generating second time randomly. The above code only will display only any random image.

My thought is, I have to store the random image in an array and check the array every time with newly created random image. If the new random image is not in that array, I need to display that image,else I have to find another image.

I created the below code with above thought.

  $allimgs=array();
  $dire="images/";
  $images = glob($dire. '*.{jpg,jpeg,png,gif}', GLOB_BRACE);
  $randomImage = $images[array_rand($images)];

   if(!in_array($randomImage,$allimgs))
   {
     $allimgs[]=$randomImage;
     <input type="image" src="<?=$randomImage;?>" alt="<?=$randomImage;?>" />
   }

But I am still stuck with this code. Anyone please help to improve this code? or any other idea?

Thanks.

Answer 1

One solution might be to do this:

<?
// initialize $images
shuffle($images);
$randomImage = array_pop($images);
?>
<input type="image" src="<?=$randomImage;?>" alt="<?=$randomImage;?>" />

This will guarantee that you use each image only once, in a random order.