Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have:

std::cout << "Start = " << std::dec << (&myObject) << std::endl;

to output an address in decimal. However, the address is still coming out in hex??

(I am outputting one of these for each of ten members, so I don't want to assign each one to a variable and then std::dec the variable separately)

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
710 views
Welcome To Ask or Share your Answers For Others

1 Answer

The hex and dec manipulators are for integers, not pointers. Pointers are always rendered in the form that printf's %p formatter would have used on your system (which is, usually, hexadecimal notation).

This helps to emphasise the fact that pointers and numbers are distinct. You may consider it to be one of the rare cases in which number semantics and number representation are, to some degree, coupled.

The best you can do is to cast the pointer to uintptr_t before streaming it:

std::cout << "Start = " << std::dec << uintptr_t(&myObject) << std::endl;

…but please consider whether you really need to do so.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...