Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I understand that it's removing the first 3 elements of the array and adding them to the new array. But how does the function continue to add ensuing chunks of the array to the new array variable?

How does the while loop work without proper conditions?

How does it work in collaboration with splice() here?

function chunkArrayInGroups(arr, size){
  let newArr = [];
  while(arr.length){
    newArr.push(arr.splice(0, size))
  }
  return newArr;
}

chunkArrayInGroups(["a", "b", "c", "d"], 2);
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
550 views
Welcome To Ask or Share your Answers For Others

1 Answer

Conditions in js are either "truthy" or "falsy", for numbers everything except 0 is "truthy", 0 is "falsy". That means that the loop runs until the array is empty, its length 0 and therefore falsy.

 if(0) alert("never");
 if(1) alert("always");
 let i = 3;
 while(i) console.log(i--);

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...