### 问题描述el-table-column
,设type
属性为selection
后,不能通过v-if或v-show隐藏
### 问题出现的环境背景及自己尝试过哪些方法
### 相关代码
粘贴代码文本
<el-tabs v-model="activeName" @tab-click="handleFilter">
<el-tab-pane label="待处理" name="0"/>
<el-tab-pane label="已处理" name="1"/>
</el-tabs>
<el-table v-loading="loading" ref="multipleTable" :data="tableData" highlight-current-row border fit @selection-change="handleSelectionChange">
<el-table-column v-if="activeName==='0'" type="selection"/>
<el-table-column label="姓名" prop="memberName" align="left" width="120px"/>
<el-table-column label="单位" prop="deptName" align="left"/>
<el-table-column label="校验类型" prop="verifyResultType" align="left">
<template slot-scope="scope">
{{ scope.row.verifyResultType | verifyResultTypeFilter }}
</template>
</el-table-column>
<el-table-column label="校验方式" prop="verifyType" align="left">
<template slot-scope="scope">
{{ scope.row.verifyType | verifyTypeFilter }}
</template>
</el-table-column>
<el-table-column label="校验时间" prop="verifyAddTime" align="left"/>
<el-table-column v-if="activeName==='1'" prop="verifyProcessUser" label="处理人" align="left"/>
<el-table-column v-if="activeName==='1'" prop="verifyProcessTime" label="处理时间" align="left"/>
<el-table-column v-if="activeName==='0'" label="操作" align="left">
<template slot-scope="scope">
<el-button v-if="activeName==='0'" type="text" @click="handleDeal(scope)">处理</el-button>
<el-button v-if="activeName==='0'" type="text" @click="handleIgnore(scope)">忽略</el-button>
<!-- <el-button type="text" @click="handleView(scope)">查看</el-button> -->
</template>
</el-table-column>
</el-table>