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I want my Spring MVC application to redirect to a dynamic URL (submitted by the user). So if I have code like this,

@RequestMapping("/redirectToSite")
protected ModelAndView redirect(
    @RequestParam("redir_url") String redirectUrl,
    HttpServletRequest request, 
    HttpServletResponse response) 
{
    // redirect to redirectUrl here
    return ?
}

what should I write to redirect to the submitted URL? For instance http://mySpringMvcApp/redirectToSite?redir_url=http://www.google.com should redirect to Google.

question from:https://stackoverflow.com/questions/9311940/redirect-to-dynamic-url-in-spring-mvc

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1 Answer

Try this:

@RequestMapping("/redirectToSite")
protected String redirect(@RequestParam("redir_url") String redirectUrl) 
{
    return "redirect:" + redirectUrl;
}

This is explained in 16.5.3.2 The redirect: prefix of Spring reference documentation. Of course you can always do this manually:

response.sendRedirect(redirectUrl);

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