python - Standard deviation in numpy

Question

(This question already has answers here): question from:https://stackoverflow.com/questions/34050491/standard-deviation-in-numpy

Answer 1

By default, numpy.std returns the population standard deviation, in which case np.std([0,1]) is correctly reported to be 0.5. If you are looking for the sample standard deviation, you can supply an optional ddof parameter to std():

>>> np.std([0, 1], ddof=1)
0.70710678118654757

ddof modifies the divisor of the sum of the squares of the samples-minus-mean. The divisor is N - ddof, where the default ddof is 0 as you can see from your result.