unix - Find the line number where a specific word appears with "grep"

Question

(Closed.) This question is off-topic. It is not currently accepting answers. question from:https://stackoverflow.com/questions/10589929/find-the-line-number-where-a-specific-word-appears-with-grep

Answer 1

Use grep -n to get the line number of a match.

I don't think there's a way to get grep to start on a certain line number. For that, use sed. For example, to start at line 10 and print the line number and line for matching lines, use:

sed -n '10,$ { /regex/ { =; p; } }' file

---

To get only the line numbers, you could use

grep -n 'regex' | sed 's/^([0-9]+):.*$/1/'

Or you could simply use sed:

sed -n '/regex/=' file

Combining the two sed commands, you get:

sed -n '10,$ { /regex/= }' file