c++11 - How is hexadecimal number 0x3F converted into decimal?

Question

This question already has answers here: question from:https://stackoverflow.com/questions/65937304/how-is-hexadecimal-number-0x3f-converted-into-decimal

Answer 1

The type of 0x3F is int, just as the type of 63 is int. The hexadecimal prefix only means the digits are in base-16 instead of base-10.

'?' is a character literal, of type char. That is also an integral type. memset technically wants an int, but a char will convert to int.