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int* concat_tab(int n1,int t1[],int n2, int t2[]){
    int *t3;
    t3 = (int*) malloc((n1+n2)*sizeof(int));
    for (int i = 0; i < n1; i++){
            *(t3+i)=*(t1+i);}
    for (int j = 0; j < n2; j++){
            *(t3+n1+j)=*(t2+j);}
    
    for (int i = 0; i < n1+n2; i++){
        printf("%d",*(t3+i));}
}

I'm trying to use this function two arrays but I get a segmentation fault. Any Help!

question from:https://stackoverflow.com/questions/65904989/contactenating-two-arrays-in-c-using-pointers-and-function

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1 Answer

Your function doesn't have a return t3; statement.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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