x86 - Assembly, printing ascii number

Question

I have a problem with my assembly code. I want to print number stored in register cx, but when i tried to print it, it printed ascii character instead of ascii number, so I decided to write a procedure to convert ascii char to ascii value. Problem is, that when I try to call that procedure, the program freezes and I have to restart dosbox. Does anyone know whats wrong with this code? Thanks.

P4      PROC                
            MOV AX,CX           ;CX = VALUE THAT I WANT TO CONVERT
            MOV BX,10           
    ASC2:
            DIV BX              ;DIV AX/10
            ADD DX,48           ;ADD 48 TO REMAINDER TO GET ASCII CHARACTER OF NUMBER 
            PUSH AX             ;SAVE AX
            MOV AH,2            ;PRINT REMAINDER STORED IN DX
            INT 21H             ;INTERRUP
            POP AX              ;POP AX BACK
            CMP AX,0            
            JZ EXTT             ;IF AX=0, END OF THE PROCEDURE
            JMP ASC2            ;ELSE REPEAT
    EXTT:
            RET
    P4      ENDP

Answer 1

Something like this would work better for printing a decimal value (the new code is in lowercase):

        mov byte [buffer+9],'$'
        lea si,[buffer+9]

        MOV AX,CX           ;CX = VALUE THAT I WANT TO CONVERT
        MOV BX,10         
ASC2:
        mov dx,0            ; clear dx prior to dividing dx:ax by bx
        DIV BX              ;DIV AX/10
        ADD DX,48           ;ADD 48 TO REMAINDER TO GET ASCII CHARACTER OF NUMBER 
        dec si              ; store characters in reverse order
        mov [si],dl
        CMP AX,0            
        JZ EXTT             ;IF AX=0, END OF THE PROCEDURE
        JMP ASC2            ;ELSE REPEAT
EXTT:
        mov ah,9            ; print string
        mov dx,si
        int 21h
        RET

buffer: resb 10

Instead of printing each character directly it adds the characters to a buffer in reverse order. For the value 123 it would add '3' at buffer[8], '2' at buffer[7] and '1' at buffer[6] - so if you then print the string starting at buffer+6 you get "123".
I'm using NASM syntax but hopefully it should be clear enough.