average - Trying to calculate highest marks with name in python

Question

grade=[]
names=[]
highest=0



cases=int(input('Enter number of cases: '))
for case in range(1,cases+1):
    print('case',case)

    number=int(input('Enter number of students: '))
    for numbers in range (1,number+1):

        name=str(input('Enter name of student: '))
        names.append(name)
        mark=float(input('Enter mark of student:'))
        grade.append(mark)


    print('Case',case,'result') 
    print('name',list[list.index(max(grade))])
    average=(sum(grade)/number)
    print('average',average)
    print('highest',max(grade))
    print('name',names[grade.index(max(grade))])

I want to print name of the student with the highest mark. I have not learned anything other than list, while and for. NO dictionary ..nothing. I was wondering how can i do this? ALSO i am getting this error!!! builtins.AttributeError: 'str' object has no attribute 'append'. HELP. thank you! :D

Answer 1

1. for number in range (1,number+1):
   

   Don't reuse variable names for different things, call one of them numbers and the other number:

   numbers=int(input('Enter number of students: '))
   for number in range (1,numbers+1):
   

2. You made name a list in the beginning:

   name=[]
   

   but here you assign a single input to it:

   name=str(input('Enter name of student: '))
   

   The you append the new name to itself:

   name.append(name)
   

   which is not possible, because name is after the input no longer a list but a string. Again using different variable names for different things would help. Call the array names and the single input name:

   names = []
   #...
   name=str(input('Enter name of student: '))
   names.append(name)
   

3. And here:

    print('name',list[list.index(max(grade))])
   

   list is a build-in type, not one of your variables, so what you are trying to do is index a type, not a specific list. If you want to call index on a specific list you do so by using the variable name of that list. grade.index(...) will find the specific position matching the passed grade in grade and then you can use this position to get the corresponding name, because you know, that the name is at the same position in names:

   print('name',names[grade.index(max(grade))])