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In my calculator I am using these statements to calculate square root and cube root.

case "sqrt root":
        result = Math.Sqrt(number1);
break;
case "root":
     result = Math.Pow(number1, (1 / number2));
     //"for cubic root" - Math.pow(number, (1/ 3))
break;

I am not very familiar with Math.Pow. Is there another way to calculate cube root? With Math.Sqrt?

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You'd need to do it with floating point division (doing 1/3 does integer division, which wouldn't work)

result = Math.Pow(number, (1.0 / 3.0));

But otherwise no, there's no built-in function for cubic root


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