how to pass parameter to php function and call in html

Question

I have this function in php; a separate file, function dbRowInsert($table_name, $form_data).

I included it in my php file in which registration happens. My problem is how do I call the function on form submit and pass a parameter to the dbRowInsert function. This is the data of my form:

$form_data = array(
    'username' => $username,
    'password' => $password,
    'title' => $title,
    'first_name' => $first_name,
    'middle_name' => $middle_name,
    'last_name' => $last_name,
    'position' => $position,
    'residence' => $residence,
    'monthly_salary' => $monthly_salary,
);  

I tried this method:

<form id="signup_form" class="form-horizontal" role="form" action="<?php dbRowInsert(tblperson, $form_data) ?>">  
...
</form>

Answer 1

PHP is not written like JavaScript; a POST request must be sent to a PHP page for processing (unless you're using AJAX), like so

<form method="POST" action="process.php">
....
</form>

In process.php, you have to extract out the fields you want to send to the function.

$username = $_POST['username'];
doSomethingWIthUserName($username);

Or in you case, since you are sending the entire array:

dbRowInsert("tblHelpers", $_POST);

Here's a detailed tutorial on handling POST requests.