Displaying database's row value in javascript function in PHP

Question

$finalval=0;
while($row = mysql_fetch_array($result))
{
 $finalval=$finalval. "<a href='#' 
 onClick='showContent(".json_encode($row['ID']).")'>".  $row['Title'] . "</a> <br>" ;

}
echo  $finalval;

<script language="javascript" type="text/javascript"  >
 function showContent(value)
 {
 alert(value);
 }
</script>

Please rectify my error alert box is displaying null instead of ID value.Thanks

Answer 1

When you call showContent(), you have to put the ID you want to show between ", like this:

$finalval=$finalval. "<a href='#' onClick='showContent("".json_encode($row['ID'])."");'>".  $row['Title'] . "</a> <br>"