I have this matrix:
A <- matrix(c(1,2,4,3,5,7,5,7,6,6,9,
5.9,9,11,8,4.5,5.5,7.9,
21,6.7,13.6,3.5,5,6,6,
7.9,1,67,4,2), ncol=3, byrow=T)
and this vector:
B <- c(2 ,3, 4)
I would this expected result:
X1 X2 X3
[1,] 4.0 14.0 22.9
[2,] 8.0 21.0 26.9
[3,] 11.0 27.0 27.8
[4,] 15.0 25.5 35.4
[5,] 13.5 23.2 35.5
[6,] 25.5 17.2 28.5
[7,] 24.5 19.6 22.6
[8,] 9.5 16.9 NA
[9,] 73.0 NA NA
[10,] NA NA NA
# the operation under the eventually code is:
col 1:
A[1,1]+A[2,1]=1+3=4 # first result for first column.
A[2,1]+A[3,1]=3+5=8 # second result for first column
. . .
A[9,1]+A[10,1]=6+67= 73 #last expected result for first column
col 2 :
A[1,2]+A[2,2]+A[3,2]=2+5+7=14 # first result for second column.
A[2,2]+A[3,2]+A[4,2]=5+7+9=21 # second result for second column
. . .
A[8,2]+A[9,2]+A[10,2]=5+7.9+4=16.9 #last expected result for second column
and so on for the third columns of matrix A accordingly to the values of vector B.
I tried with this code:
res <- data.frame(matrix(ncol=ncol(A),nrow=nrow(A)))
res_tot <- data.frame(matrix(ncol=ncol(A),nrow=nrow(A)))
for (j in 1:ncol(A)){
for(t in 1:nrow(A)){
res <- A[t+B[j],j]
res_tot[t,j] <- res
}
}
but the index are not correct. Now, I would, if is possible, the code only with for
loop and use of index(like i,j,k
etc...) without function like mapply,rollSum, etc.. from packages.
Is it possible? please...