c++ - count number of times a character appears in an array?

Question

i've been thinking for a long time and havent got anywhere with the program. i dont know where to begin. The assignment requires use of single function main and only iostream library to be used. the task is to Declare a char array of 10 elements. Take input from user. Determine if array contains any values more than 1 times . do not show the characters that appears 1 time only.

Sample output:
a 2
b 4
..

a an b are characters. and 2 and 4 represents number of times they appear in the array B.

i tried to use nested loop to compare a character with all the character in array and incrementing a counter each time similer character id sound but unexpected results are occuring.

Here is the code

#include <iostream>
using namespace std;
void main()
{

    char ara[10];
    int counter=0;
    cout<<"Enter 10 characters in an array
";
    for ( int a=0; a<10; a++)
        cin>>ara[a];

    for(int i=0;  i<10;  i++)
    {
       for(int j=i+1; j<10;  j++)
     {
         if(ara[i] == ara[j])
               {
                  counter++;
                  cout<<ara[i]<<"	"<<counter<<endl;
               }
     }
    }
}

Answer 1

Algorithm 2: std::map
Declare / define the container:

std::map<char, unsigned int> frequency;

1. Open the file
2. read a letter.
3. find the letter: frequency.find(letter)
4. If letter exists, increment the frequency: frequency[letter]++;
5. If letter no exists, insert into frequency: frequency[letter] = 1;
6. After all letters processed, iterate through the map displaying the letter and its frequency.