php - Multiple MYSQLi prepared statements

Question

I am just learning how to use MYSQLi prepared statements so please go easy on me. I can get these to work individually but when I put them together they don't work.

$con = my connection details. 

This is my code for the queries:

// Insert the review into DB 
$stmt = $con->prepare("INSERT INTO reviews (order_id, comment) VALUES (?, ?)");
$stmt->bind_param('is', $order_id, $comment);
$stmt->execute(); 
$stmt->close();


// Update transactions to show review added
$stmt = $con->prepare("UPDATE transactions SET review = ? WHERE order_id = ?");
$stmt->bind_param('ii', 1, $order_id);
$stmt->execute(); 
$stmt->close(); 

Thanks in advance for your help! Much appreciated.

Answer 1

your code is good however you should dont name them the same name $stmt

the first statment is $stmt

then give second statment other name like $stmt2. or what ever name you like.

example:

$stmt = $con->prepare("INSERT INTO reviews (order_id, comment) VALUES (?, ?)");
$stmt->bind_param('is', $order_id, $comment);
$stmt->execute(); 
$stmt->close();


// Update transactions to show review added
$stmt2 = $con->prepare("UPDATE transactions SET review = ? WHERE order_id = ?");
$stmt2->bind_param('ii', 1, $order_id);
$stmt2->execute(); 
$stmt2->close(); 

and to debug your code and see where is the error use this.

if ($stmt = $con->prepare("INSERT INTO reviews (order_id, comment) VALUES (?, ?)") ){
   $stmt->bind_param('is', $order_id, $comment);
   $stmt->execute(); 
   $stmt->close();
    }
 else {printf("Error message:: %s
", $con->error);}