Check if any number in array is bigger than given number Javascript

Question

I have this function which finds the avarage in the array :

const findAvarage = (a,b,c,d) =>{
  let total = 0;
  let numbers = [a,b,c,d];

for(let i = 0; i < numbers.length; i++) {
    total += numbers[i];
}
let avg = total / numbers.length;

console.log("avg",avg)
}

findAvarage(2,2,6,10);

Now I need to find out index of number in the array which is bigger than the avarage number,Any suggestions please?

Answer 1

You can achieve this with the find() method:

const array1 = [2, 2, 6, 10];

const found = array1.find(element => element > findAvarage(2,2,6,10));

console.log(found);

If you want to get back the index of the element, use findIndex() instead

Source: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find