floating point - Java division for double and float without E

Question

I'm doing some large number divisions (long/long to double, and int/int to float).. But I bump, to a problem when the results include the "E". I know we can use NumberFormat to format when displaying, but that's not what I. Just want the result of the divisions to not involve the "E", i.e. just round it up to the closest float/double that fits in the space.

Anybody got an idea?

Answer 1

The internal representation of floating point number does not have a switch for E presence or not (check IEEE-754). So your float/double number is just number (not a number with E or without it).

The only place where you get E is when you print this value out. And while Java uses number formater for printing, so I don't see a point why you don't want to use it here.

System.out.println(new DecimalFormat("#.#####").format(doubleValue));