java - Counting the amount of highest number in a string

Question

I am trying to output the amount of times the highest number appears in the user input for example user inputs 2 4 3 4 2 4 0 the highest number is 4 and it appears 3 times, not sure how to go about it.

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner keyboard = new Scanner(System.in);

    String number, last;

    System.out.println("Enter an interger (0 ends the input): ");
    number = keyboard.nextLine();
    last = number.substring(number.length() - 1);

    while(!last.equals("0")){
        System.out.println("Must end the input with a 0: ");
        number = keyboard.nextLine();
        last = number.substring(number.length() - 1);
    }

    String[] array = number.split(" ");

    int max = Integer.MIN_VALUE, maxIndex = 0;

    int count;

    for (int i = 0; i < array.length; i++) {
         if (Integer.parseInt(array[i]) > max) {
             max = Integer.parseInt(array[i]);
             maxIndex = i;
         }
    }
    //String repeat = number.);
    System.out.println("The largest number is " + max);
}

Answer 1

You can do it using Java 8's streams, e.g.:

String number = "2 4 3 4 2 4 0";
String[] array = number.split(" ");
TreeMap<Integer,Long> numberMap = Arrays.stream(array)
    .map(s -> Integer.parseInt(s))
    .collect(Collectors.groupingBy(Function.identity(), TreeMap::new, Collectors.counting()));
System.out.println(numberMap.descendingMap().firstEntry().getValue());

This basically stores each number and it's count into a Map. As the Map we are using is TreeMap, it sorts the keys in ascending order. We then get the last (i.e. highest) key from it and print the corresponding value which is 3.