Why does this string comparison give that result in ruby?

Question

k=[]

path="E:/expr/amit.txt"
name="amit"

File.open("amit.txt").each do |l| 
  k<< l
end

puts k[0]
puts name.eql?("k[0]")

O/p amit

false

why o/p containing false??it should give true

Answer 1

The value of name is "amit". You're checking whether the string "amit" is equal to the string "k[0]". It's not, so you get false.

What you probably meant to do was name.eql?(k[0]), which would check whether the value k[0] is "amit". However this would still return false, because k[0] is "amit ", not "amit".

To fix this, you should do k << l.chomp instead of k << l to remove the trailing .