swift - Use multiple launch paths to run terminal command swfit

Question

I'm trying show hidden files in Finder by running a terminal command. The problem is it looks like defaults write com.apple.finder AppleShowAllFiles TRUE has multiple launch paths. When I run the which command in terminal followed by the command I'm trying to run, it gives me three paths: /usr/bin/defaults, /usr/bin/write, and /usr/bin/TRUE. I can't set all three as launch paths for the command because .launchPath doesn't accept an array.

How can I run this command?

edit: The problem was I wasn't separating the arguments into separate strings. This code works:

@IBAction func showAllFiles(_ sender: NSMenuItem) {
    let task = Process()
    task.launchPath = "/usr/bin/defaults"
    task.arguments = ["write", "com.apple.finder", "AppleShowAllFiles", "TRUE"]
    task.launch()
    task.waitUntilExit()
}

Answer 1

You're looking for /usr/bin/defaults. The reason you're getting this output is because the following command:

which defaults write com.apple.finder AppleShowAllFiles TRUE

is like doing:

which defaults
which write
which com.apple.finder
which AppleShowAllFiles
which TRUE

which prints:

/usr/bin/defaults

/usr/bin/write

(nothing)

(nothing)

(nothing)

/usr/bin/TRUE