Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I have two sets of dates

Testday<-as.Date(c("2015-06-25", "2015-06-25","2015-06-25"))
DOB<-as.Date(c("2012-03-15", "2004-04-21","2014-07-25"))

I want to calculate the age, correct to 2 decimal places.

On Excel, I would simply do this: (Testday - DOB)/365.25

and obtain these ages: 3.28, 11.18, 0.92

Is there anyway I could perform this on R too?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
210 views
Welcome To Ask or Share your Answers For Others

1 Answer

Is this OK?

round(as.numeric((Testday - DOB) / 365.25), 2)
#[1]  3.28 11.18  0.92

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...