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I'm trying to search the regular expression pattern and, if it matches, find whether the value of that pattern exists inside any tag of the form <sec id="sec123"> in a file. If it does, I want to replace it with result1. I think it can be done with the MatchEvaluator function, but I can't figure out how to apply it.

I'm new to VB.NET (and programming in general) and really don't know what to do. This is what I've tried so far:

Dim pattern As String="(?<=rid="sec)(\d+)(?=">)"
Dim r As Regex = New Regex(pattern)
Dim m As Match = r.Match(input)
If (m.Success) Then
    Dim x As String=" id=""sec"+ pattern +""""
    Dim r2 As Regex = New Regex(x)
    Dim m2 As Match = r2.Match(input)
    If (m2.Success) Then
        Dim tgPat AsString="<xref ref-type="section" rid=""sec + pattern +"">(w+) (d+)</xref>"
        Dim tgRep As String= "$1 $2"
        Dim tgReg As New Regex(tgPat)
        Dim result1 As String = tgReg.Replace(input, tgRep)
    Else
    EndIf
EndIf
Next

sample input:

<sec id="sec1">
<p>"You fig. 23 did?" I <xref ref-type="section" rid="sec12">section 12</a> asked, surprised.</p>
<p>"There are always better terms <xref ref-type="section" rid="sec6">section 6</a>, Richard!" my mom said sharply.</p>
<p>I <xref ref-type="section" rid="sec2">section 2</a> stood. I <xref ref-type="section" rid="sec2">section 2</a> had to hurry if I <xref ref-type="section" rid="sec1">section 1</a> was going to get to work on time.
<fig id="fig4">
<caption><p>I'm confused</p></caption>
</fig> 
</p>
<p>Turning to face her, I <xref ref-type="section" rid="sec2">section 2</a> walked backward. "I"ve seriously got to get ready. Why don"t we get together for lunch and talk more then?"</p>
<sec id="sec2">
<p>"You fig. 23 can"t be""</p>
<p>I <xref ref-type="section" rid="sec4">section 4</a> adored the Art Deco elegance of the Chrysler Building. I <xref ref-type="section" rid="sec2">section 2</a> could pinpoint my place on the island in relation to the posit table 9ion of the Empire State Building.</p>
<p>I <xref ref-type="section" rid="sec1">section 1</a> felt Gideon before I <xref ref-type="section" rid="sec1">section 1</a> saw him, my entire body humming wit table 9h awareness as he stepped out of the Bentley, which had pulled up behind the Benz.</p>
</sec>
</sec>

expected output:

<sec id="sec1">
<p>"You fig. 23 did?" I **section 12** asked, surprised.</p>
<p>"There are always better terms **section 6**, Richard!" my mom said sharply.</p>
<p>I <xref ref-type="section" rid="sec2">section 2</a> stood. I <xref ref-type="section" rid="sec2">section 2</a> had to hurry if I <xref ref-type="section" rid="sec1">section 1</a> was going to get to work on time.
<fig id="fig4">
<caption><p>I'm confused</p></caption>
</fig> 
</p>
<p>Turning to face her, I <xref ref-type="section" rid="sec2">section 2</a> walked backward. "I"ve seriously got to get ready. Why don"t we get together for lunch and talk more then?"</p>
<sec id="sec2">
<p>"You fig. 23 can"t be""</p>
<p>I **section 4** adored the Art Deco elegance of the Chrysler Building. I <xref ref-type="section" rid="sec2">section 2</a> could pinpoint my place on the island in relation to the posit table 9ion of the Empire State Building.</p>
<p>I <xref ref-type="section" rid="sec1">section 1</a> felt Gideon before I <xref ref-type="section" rid="sec1">section 1</a> saw him, my entire body humming wit table 9h awareness as he stepped out of the Bentley, which had pulled up behind the Benz.</p>
</sec>
</sec>
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1 Answer

I've replaced my initial solution with one which uses XElement as your data isn't as straightforward as I initially thought.

    Dim input = XElement.Parse(data)
    Dim sections = input.Descendants("sec").ToDictionary(Function(s) s.@id, Function(s) s)
    Dim xrefs = input.Descendants("xref").ToLookup(Function(s) s.@rid, Function(s) s)

    For Each group In xrefs
        Dim section As XElement
        If sections.TryGetValue(group.Key, section) Then
            For Each xref In group
                xref.ReplaceWith(section)
            Next
        End If
    Next
    Dim output = input.ToString()

I think this does what you're after although I don't trust your data as Section2 seems to be recursive. Have a try and see what you think anyway. Steps:

  1. Parse the xml
  2. Extract the sections and key them by id in a dictionary
  3. Extract the xrefs (multiple with same key) add them by id to a Lookup
  4. For each xref check if it has a section. If it does then replace it.
  5. Extract the result.

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