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I have a file that looks like this

=sjkc(11,32as%2dc 32,43)a-b,49,26),b.'47,28n,a=64  and so on...

The objective is to retrieve all the Digits while ignoring any other characters in between. There is no newline so the coordinates are just continuous throughout the file.

Note: Not allowed to use regex and map

So for this instance, it should return the number 11 then 32 then 2 then 32 and so on...

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1 Answer

You are not asking for CSV parsing — you ignore field boundaries — you just want to extract all numbers from a string.

Do that by replacing everything that is not a number with spaces, then using a stringstream to extract.

#include <algorithm>
#include <cctype>
#include <iostream>
#include <sstream>
#include <string>

int main()
{
  std::string s = "=sjkc(11,32as%2dc 32,43)a-b,49,26),b.'47,28n,a=64";

  std::transform( s.begin(), s.end(), s.begin(), []( char c ) 
  { 
    return std::isdigit( c ) ? c : ' ';
  } );

  std::istringstream ss( s );
  int n;
  while (ss >> n)
    std::cout << n << "
";
}

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