vim - Find all submatches to reorder a sentence

Question

Using gvim 8.0 on windows 7, I'd like to reorder parts of a sentence pattern:

before:

Execution time: 0.22s Statement 1 of 8 finished (2018-05-18 06:48:35.231)
Execution time: 0.22s Statement 1 of 8 finished (2018-05-18 06:54:01.259)
Execution time: 0.22s Statement 1 of 8 finished (2018-05-18 07:05:54.480)
<et al>

after:

Statement 1 of 8 finished (2018-05-18 06:48:35.231) Execution time: 0.22s 
Statement 1 of 8 finished (2018-05-18 06:54:01.259) Execution time: 0.22s
Statement 1 of 8 finished (2018-05-18 07:05:54.480) Execution time: 0.22s 
<et al>

I thought I would capture submatches, and then substitute; I can't seem to get more than one submatch - I tried:

/v^([^S]*)

and that matched the first submatch I want, but then:

/v^([^S]*),([^S]*)

doesn't seem to find anything.

Is this the right approach? What am I doing wrong?

Answer 1

For your input sentences you could use the substitution:

 %s/v(.*) (Statement.*)/2 1/g

This will capture the text before Statement and put it at the end of the sentence. Output:

Statement 1 of 8 finished (2018-05-18 06:48:35.231) Execution time: 0.22s
Statement 1 of 8 finished (2018-05-18 06:54:01.259) Execution time: 0.22s
Statement 1 of 8 finished (2018-05-18 07:05:54.480) Execution time: 0.22s