digits sum of a number (c)

Question

I need to find the sum of the digits of a number with five digits. For example, the sum of the digits of the number 3709 is 3 + 7 + 0 + 9 = 19.

#include <stdio.h>

int main()
{
    int sum;
    char digit_1, digit_2, digit_3, digit_4, digit_5;
    printf("Plase enter a five digit number
");
    scanf("%c,%c,%c,%c,%c", &digit_1, &digit_2, &digit_3, &digit_4, &digit_5);
    sum = digit_1 + digit_2 + digit_3 + digit_4 + digit_5;
    printf("the sum of the digits is: %d", sum);

    return 0;
}

output:

plase enter a five digit number                                       
3709                                                                  
the sum of the digits is 51

For some reason it doesn't show to correct answer and i can't seem to find whats wrong.

Answer 1

The problem with your code is

your scanf needs , separated inputs

scanf("%c,%c,%c,%c,%c", ...)

Hence when you enter 3709 only digit1 will be read and rest will be omitted by scanf. You can check the return value of scanf to verify.

and ASCII value of 3 is 51 thus you are getting 51 as output.

---

Try this

scanf("%c%c%c%c", &digit_1 ,&digit_2 ,&digit_3 ,&digit_4 );

int sum = (digit_1 -'0')+(digit_2 -'0')+(digit_3 -'0')+(digit_4 -'0');