Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

If I try to write a method like below

public void someStuff(Object ... args, String a )

I get this error

The variable argument type Object of the method someStuff must be the last parameter.

I don't fully understand the requirement of variable argument type to be the last. Any inputs will be helpful.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
372 views
Welcome To Ask or Share your Answers For Others

1 Answer

The variable argument has to be the last so the compiler can work out which argument is which.

For example, say you pass

"test", "test", "test", "test"

into your function

public void someStuff(Object ... args, String a)

Java cannot work out if you want the args variable to contain 3 or 4 strings. It may be obvious to you at the time of writing but it's ambiguous.

However, when it's the other way around

public void someStuff(String a, Object ... args)

The Java compiler sees the first string, stick it into "a" and then knows that the remaining strings can be safely put into args and there is no ambiguity over the variables.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...