php - A conditional element inside an array(...) construct

Question

My system sends a configuration array to a function like this:

callThatFunction( array(k1 => v1,  k2 => v2, ... kn=vn));

I want to make one of the key value pairs, conditional upon some circumstances.

Can I do this without creating a variable for the array (and this breaking the clean config syntax that someone else had created)?

Like this

callThatFunction ( array(
k1 => v1, 
if($cond( {k2 => v2,} 
... 
kn=vn));

The above is obviously wrong syntactically, but should express my idea.

Thank you

Answer 1

You can use the conditional operator cond ? true-expr : false-expr:

$someConfig = array(
    'k1' => 'v1',
    'k2' => $cond ? 'v2a' : 'v2b'
);

The conditional expression $cond ? 'v2a' : 'v2b' will yield 'v2a' if $cond evaluates to true and 'v2b' otherwise. But this works only with the value of a key.

If you only want to add a key based on a condition, you need to use a separate if:

$someConfig = array('k1' => 'v1');
if ($cond) {
    $someConfig['k2'] = 'v2';
}

---

Edit????You can add keys conditionally without a variable using the array union operator or array_merge:

array('k1' => 'v1') + ($cond ? array('k2' => 'v2') : array())
array_merge(array('k1' => 'v1'), $cond ? array('k2' => 'v2') : array())

Now you need to decide what’s more readable or better to maintain.