php regex word boundary matching in utf-8

Question

I have the following php code in a utf-8 php file:

var_dump(setlocale(LC_CTYPE, 'de_DE.utf8', 'German_Germany.utf-8', 'de_DE', 'german'));
var_dump(mb_internal_encoding());
var_dump(mb_internal_encoding('utf-8'));
var_dump(mb_internal_encoding());
var_dump(mb_regex_encoding());
var_dump(mb_regex_encoding('utf-8'));
var_dump(mb_regex_encoding());
var_dump(preg_replace('/wei?/iu', 'weiss', 'wei?bier'));

I would like the last regex to replace only full words and not parts of words.

On my windows computer, it returns:

string 'German_Germany.1252' (length=19)
string 'ISO-8859-1' (length=10)
boolean true
string 'UTF-8' (length=5)
string 'EUC-JP' (length=6)
boolean true
string 'UTF-8' (length=5)
string 'wei?bier' (length=9)

On the webserver (linux), I get:

string(10) "de_DE.utf8"
string(10) "ISO-8859-1"
bool(true)
string(5) "UTF-8"
string(10) "ISO-8859-1"
bool(true)
string(5) "UTF-8"
string(9) "weissbier"

Thus, the regex works as I expected on windows but not on linux.

So the main question is, how should I write my regex to only match at word boundaries?

A secondary questions is how I can let windows know that I want to use utf-8 in my php application.

Answer 1

Even in UTF-8 mode, standard class shorthands like w and are not Unicode-aware. You just have to use the Unicode shorthands, as you worked out, but you can make it a little less ugly by using lookarounds instead of alternations:

/(?<!pL)wei?(?!pL)/u

Notice also how I left the curly braces out of the Unicode class shorthands; you can do that when the class name consists of a single letter.