Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I'm trying to fix a Thread error for one of my preferred examples from java code geeks.

Here's the code:

public class JsonParsingActivity extends Activity {

        String url = "http://search.twitter.com/search.json?q=javacodegeeks";

        @Override
        public void onCreate(Bundle savedInstanceState) {

            super.onCreate(savedInstanceState);
            setContentView(R.layout.main);

            new RetreiveFeedTask().execute(url);

        }
    }

The RetrieveFeedTask:

public class RetreiveFeedTask extends
        AsyncTask<String, Void, JsonParsingActivity> {

    private Exception exception;
    String url = "http://search.twitter.com/search.json?q=javacodegeeks";

    protected JsonParsingActivity doInBackground(String... urls) {
        try {

            InputStream source = retrieveStream(url);

            Gson gson = new Gson();

            Reader reader = new InputStreamReader(source);

            SearchResponse response = gson.fromJson(reader, SearchResponse.class);

            // Toast.makeText(this, response.query, Toast.LENGTH_SHORT).show();

            List<Result> results = response.results;

            for (Result result : results) {
                Toast.makeText(JsonParsingActivity.class, result.fromUser, Toast.LENGTH_SHORT).show();
            }

        } catch (Exception e) {
            this.exception = e;
            return null;
        }
    }

    protected void onPostExecute(JsonParsingActivity feed) {
        // TODO: check this.exception
        // TODO: do something with the feed
    }

    private InputStream retrieveStream(String url) {

        DefaultHttpClient client = new DefaultHttpClient();

        HttpGet getRequest = new HttpGet(url);

        try {

            HttpResponse getResponse = client.execute(getRequest);
            final int statusCode = getResponse.getStatusLine().getStatusCode();

            if (statusCode != HttpStatus.SC_OK) {
                Log.w(getClass().getSimpleName(), "Error " + statusCode
                        + " for URL " + url);
                return null;
            }

            HttpEntity getResponseEntity = getResponse.getEntity();
            return getResponseEntity.getContent();

        } catch (IOException e) {
            getRequest.abort();
            Log.w(getClass().getSimpleName(), "Error for URL " + url, e);
        }

        return null;

    }}

What's the best way to do that without errors? It's currently giving a Toast error (?).

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
392 views
Welcome To Ask or Share your Answers For Others

1 Answer

You can't do UI stuff in doInBackground(). Hence, you can't display a Toast there. You need to move this to onPostExecute() or somewhere else. Possibly onProgressUpdate()

You could call publishProgress(results) and show the Toast in onProgressUpdate() or return results to onPostExecute() and display it there. You also have the option of sending the data back to an Activity method

AsyncTask


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...