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I have this PHP code:

$end=date('Y-m-d');

I use it to get the current date, and I need the date 5 years in the future, something like:

$end=date('(Y + 5)-m-d');

How can I do this?

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Try with:

$end = date('Y-m-d', strtotime('+5 years'));

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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