I have a dictionary of swear words in the database, and the following works great
preg_match_all("/".$f."(?:ing|er|es|s)?/si",$t,$m,PREG_SET_ORDER);
$t is the input text and simply, $f = preg_quote("punk"); "punk" is from the database dictionary, so at this point in the loop the expression is as follows
preg_match_all("/punk(?:ing|er|es|s)?/si",$t,$m,PREG_SET_ORDER);
preg_quote replaces symbols eg. # with \# so that the expression is escaped, but when the dictionary is checking eg. "F@CK" or "A$$" these symbols are not detected in the input string with the above expression, I have both a$$ and f@ck in the dictionary, but they do not work. If I remove preg_quote() on the word, the regular expression is invalid as these symbols are not escaped.
Any suggestions on how I can detect "a$$" ???
Edit:
So I guess the expression that is not working as intended would be eg.
preg_match_all("/f@ck(?:ing|er|es|s)?/si",$t,$m,PREG_SET_ORDER);
Which should find f@ck in $t
UPDATE:
This is my usage, simply put; if there are matches in $m replace them with "****", this whole block is inside a loop through each word in the dictionary, $f is the dictionary word and $t is the input
$f = preg_quote($f);
preg_match_all("/$f(?:ing|er|es|s)?/si",$t,$m,PREG_SET_ORDER);
if (count($m) > 0) {
$t = preg_replace("/($f(?:ing|er|es|s)?)/si","*****",$t);
}
UPDATE:
Behold, the var_dump:
preg_quote($f) = string(5) "a$$"
$t = string(18) "You're such an a$$"
expression = string(29) "/a$$(?:ing|er|es|s)?/si"
UPDATE:
This is only happening when words end with a symbol. I tested "a$$hole" and it’s fine, but "a$$" doesn't work.
ANOTHER UPDATE:
Try this simplified version, $words being a make-shift dictionary
$words = array("a$$","asshole","a$$hole","f@ck","f#ck","f*ck");
$text = "Input whatever you feel like here eg. a$$";
foreach ($words as $f) {
$f = preg_quote($f,"/");
$text = preg_replace("/".$f."(?:ing|er|es|s)?/si",
str_repeat("*",strlen($f)),
$t);
}
I should expect to see "Input whatever you feel like here eg. ***" as a result.
