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这道题怎么做??请给大神们解释一下可以吗?


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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1楼(“四季逗”)正解。本题的关键在于:时间一致性,即狗跑的时间和哥哥追上弟弟所用的时间是一样的。公式为:s=Z(MX)/(Y-X),其中(M*X)/(Y-X)为狗跑的时间。


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
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