UPDATE: I created following generic method which can build pivot table from any collection
public static DataTable ToPivotTable<T, TColumn, TRow, TData>(
this IEnumerable<T> source,
Func<T, TColumn> columnSelector,
Expression<Func<T, TRow>> rowSelector,
Func<IEnumerable<T>, TData> dataSelector)
{
DataTable table = new DataTable();
var rowName = ((MemberExpression)rowSelector.Body).Member.Name;
table.Columns.Add(new DataColumn(rowName));
var columns = source.Select(columnSelector).Distinct();
foreach (var column in columns)
table.Columns.Add(new DataColumn(column.ToString()));
var rows = source.GroupBy(rowSelector.Compile())
.Select(rowGroup => new {
Key = rowGroup.Key,
Values = columns.GroupJoin(
rowGroup,
c => c,
r => columnSelector(r),
(c, columnGroup) => dataSelector(columnGroup))
});
foreach (var row in rows) {
var dataRow = table.NewRow();
var items = row.Values.Cast<object>().ToList();
items.Insert(0, row.Key);
dataRow.ItemArray = items.ToArray();
table.Rows.Add(dataRow);
}
return table;
}
Usage:
var table = Languagemaster.ToPivotTable(
item => item.language,
item => item.keyName,
items => items.Any() ? items.First().keyValue : null);
It has three parameters:
- column property selector which selects columns (i.e. what will be in column headers) in your case it is distinct values of languages, but it could be anything else, like date.
- row property selector - is a value which will appear in row headers, this is a what each row will be related to. Keep in mind - it is expression, not simple delegate. We need it to set column name of first column.
- data selector - this is a method which will be run on grouped data for each cell. I.e. in your case we just select
keyValue
property of first item in group. But it could be items count items => items.Count()
or anything else.
Result:
ORIGINAL ANSWER:
This query will return pivot for your data. Each item in query will have Name
(i.e. "City" in your example) and list of values - one value for each pivot column (i.e. for each language we will have value containing language name as Column
and Value
)
var languages = Languagemaster.Select(x => x.language).Distinct();
var query = from r in Languagemaster
group r by r.keyName into nameGroup
select new {
Name = nameGroup.Key,
Values = from lang in languages
join ng in nameGroup
on lang equals ng.language into languageGroup
select new {
Column = lang,
Value = languageGroup.Any() ?
languageGroup.First().keyValue : null
}
};
How to build data table from this query
DataTable table = new DataTable();
table.Columns.Add("keyName"); // first column
foreach (var language in languages)
table.Columns.Add(language); // columns for each language
foreach (var key in query)
{
var row = table.NewRow();
var items = key.Values.Select(v => v.Value).ToList(); // data for columns
items.Insert(0, key.Name); // data for first column
row.ItemArray = items.ToArray();
table.Rows.Add(row);
}
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