javascript - Load page on selection from dropdown form

Question

I am trying to make a drop down menu that takes me to various webpages. Right now it is set up so you make your selection and then you hit a "Go" button and then it takes you to the appropriate link. I am trying to figure out how to make it so when you make your selection it automatically goes and you don't need to push the "Go" button.

Here is what I have:

<p align="center">
<form name="jump" class="center">
<select name="menu">
<option value="#">Select an option</option>
<option value="/link1.shtml">Link 1</option>
<option value="/link2.shtml">Link 2</option>
<option value="/link3.shtml">Link 3</option>
</select>
<input type="button" onClick="location=document.jump.menu.options[document.jump.menu.selectedIndex].value;" value="GO">
</form>
</p>

Any help or links to explanations would be great. Thank you!

Answer 1

Try the following:

<select onchange="location = this.options[this.selectedIndex].value;">
    <option>Please select</option>
    <option value="http://www.apple.com/">Apple</option>
    <option value="http://www.bbc.com">BBC</option>
    <option value="http://www.facebook.com">Facebook</option>
</select>?

What you were looking for was 'onchange' instead of 'onsubmit'