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<?php
$host = 'http://google.com';
if($socket =@ fsockopen($host, 80, $errno, $errstr, 30)) {
echo 'online!';
fclose($socket);
} else {
echo 'offline.';
?>

I'm using the above program to get the status of site. But I always get an offline message. Is there any mistake with the code?

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Welcome To Ask or Share your Answers For Others

1 Answer

The hostname does not contain http://, that is only the scheme for an URI.

Remove it and try this:

<?php
$host = 'google.com';
if($socket =@ fsockopen($host, 80, $errno, $errstr, 30)) {
echo 'online!';
fclose($socket);
} else {
echo 'offline.';
}
?>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
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