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I am novice in javascript and jQuery. In my html have 2 radio buttons and one div. I want to show that div if I check the first radio-button but otherwise I want it to be hidden

so: If radio button #watch-me is checked --> div #show-me is visible. If radio button #watch-me is unchecked (neither are checked or the second is checked) --> div #show-me is hidden.

Here is what I have so far.

 <form id='form-id'>
<input id='watch-me' name='test' type='radio' /> Show Div<br />
<input name='test' type='radio' /><br />
<input name='test' type='radio' />
 </form>
 <div id='show-me' style='display:none'>Hello</div>

and JS:

 $(document).ready(function () { 
$("#watch-me").click(function() {
 $("#show-me:hidden").show('slow');
 });
 $("#watch-me").click(function(){
 if($('watch-me').prop('checked')===false) {
    $('#show-me').hide();}
    });
});

How should I change my script to achieve that?

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1 Answer

I would handle it like so:

$(document).ready(function() {
   $('input[type="radio"]').click(function() {
       if($(this).attr('id') == 'watch-me') {
            $('#show-me').show();           
       }

       else {
            $('#show-me').hide();   
       }
   });
});

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
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