c++ - Why is the address of this volatile variable always at 1?

Question

I wanted to inspect the address of my variable

volatile int clock;
cout << &clock;

But it always says that x is at address 1. Am i doing something wrong??

Answer 1

iostreams will cast most pointers to void * for display - but no conversion exists for volatile pointers. As such C++ falls back to the implicit cast to bool. Cast to void* explicitly if you want to print the address:

std::cout << (void*)&clock;