Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

THIS CODE UNDER HERE WORKS, you can read the answers under here - i edit this for future reference.

HTML:

<div><a href="#" id="btn">Show bank div and hide fancy div</a></div>
<div id="btn-bk"><a href="#">back</a></div>
<div id="bank">Bank Div</div>
<div id="fancy">Fancy Div</div>

CSS:

#bank {display:none;}
#btn-bk {display:none;}

Javascript:

    $('#btn').click(function(e){    
    $('#fancy, #btn').fadeOut('slow', function(){
        $('#bank, #btn-bk').fadeIn('slow');
    });
});

    $('#btn-bk').click(function(e){    
        $('#bank, #btn-bk').fadeOut('slow', function(){
            $('#fancy, #btn').fadeIn('slow');
        });
    });

Live DEMO that works

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
195 views
Welcome To Ask or Share your Answers For Others

1 Answer

Your problem is with this line of code:

$('#bank').replace('<div id="fancy"></div>').fadeIn('slow');

There is no .replace() function in jQuery. Remove that and it works:

$('#bank').fadeIn('slow');

See it here: http://jsfiddle.net/3XwZv/57/


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...