I was thinking about the performance of calling List<T>.Indexof(item)
. I am not sure if it will be a O(n) performance for a sequential algorithm or O(log(n)) performance for a binary tree??
I was thinking about the performance of calling List<T>.Indexof(item)
. I am not sure if it will be a O(n) performance for a sequential algorithm or O(log(n)) performance for a binary tree??
Using Reflector for .NET we can see:
public int IndexOf(T item)
{
return Array.IndexOf<T>(this._items, item, 0, this._size);
}
public static int IndexOf<T>(T[] array, T value, int startIndex, int count)
{
return EqualityComparer<T>.Default.IndexOf(array, value, startIndex, count);
}
internal virtual int IndexOf(T[] array, T value, int startIndex, int count)
{
int num = startIndex + count;
for (int i = startIndex; i < num; i++)
{
if (this.Equals(array[i], value))
return i;
}
return -1;
}