Before you say its a duplicate question, please let me explain (as I've read all similar threads).
My application has both of these settings:
procStartInfo.CreateNoWindow = true;
procStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
and is also has WindowsApplication as the output type.
The black window STILL comes up when I call a command line command. Is there anything else I can do to hide the window? It doesn't happen for all commands, XCOPY is a situation where it the black window does flash up. This only happens though when the destination I'm XCOPYing too already contains the file and it's prompting me if I want to replace it. Even if I pass in /Y it will still flash briefly.
I'm open to using vbscript if that will help, but any other ideas?
The client will call my executable and then pass in a command line command ie:
C:MyProgram.exe start XCOPY c:Test.txt c:ProgramFiles
Here's the full code of the application:
class Program
{
static void Main(string[] args)
{
string command = GetCommandLineArugments(args);
// /c tells cmd that we want it to execute the command that follows and then exit.
System.Diagnostics.ProcessStartInfo procStartInfo = new System.Diagnostics.ProcessStartInfo("cmd.exe", "/c " + command);
procStartInfo.RedirectStandardOutput = true;
procStartInfo.UseShellExecute = false;
// Do not create the black window.
procStartInfo.CreateNoWindow = true;
procStartInfo.WindowStyle = ProcessWindowStyle.Hidden;
System.Diagnostics.Process process = new System.Diagnostics.Process();
process.StartInfo = procStartInfo;
process.Start();
}
private static string GetCommandLineArugments(string[] args)
{
string retVal = string.Empty;
foreach (string arg in args)
retVal += " " + arg;
return retVal;
}
}
See Question&Answers more detail:os