Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

I'm working with requirejs+jquery and i was wondering if there was a smart way to make a jQuery plugin work well with require.

For example i'm using jQuery-cookie. If i understood correctly i can create a file called jquery-cookie.js and inside do

define(["jquery"], // Require jquery
       function($){
// Put here the plugin code. 
// No need to return anything as we are augmenting the jQuery object
});
requirejs.config( {
    "shim": {
        "jquery-cookie"  : ["jquery"]
    }
} );

i wondered if i could do things like jQuery does, which is like this:

if ( typeof define === "function" && define.amd && define.amd.jQuery ) {
    define( "jquery", [], function () { return jQuery; } );
}

or if this is the only way to make jQuery plugins compatible with requirejs or any amd

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
288 views
Welcome To Ask or Share your Answers For Others

1 Answer

There are some caveats with using shim configuration in RequireJS, pointed out on http://requirejs.org/docs/api.html#config-shim. Namely, "Do not mix CDN loading with shim config in a build" when you're using the optimizer.

I was looking for a way to use the same jQuery plugin code on sites both with and without RequireJS. I found this snippet for jQuery plugins at https://github.com/umdjs/umd/blob/master/jqueryPlugin.js. You wrap your plugin in this code, and it will work properly either way.

(function (factory) {
if (typeof define === 'function' && define.amd) {
    // AMD. Register as an anonymous module depending on jQuery.
    define(['jquery'], factory);
} else {
    // No AMD. Register plugin with global jQuery object.
    factory(jQuery);
}
}(function ($) {

    $.fn.yourjQueryPlugin = function () {
        // Put your plugin code here
    };  

}));

Credit goes to jrburke; like so much javascript, it's functions inside functions acting on other functions. But I think I have unpacked what it's doing.

The function argument factory in the first line is itself a function which is invoked to define the plugin on the $ argument. When no AMD-compatible loader is present, it's invoked directly to define the plugin on the global jQuery object. That's just like the common plugin definition idiom:

function($)
{
  $.fn.yourjQueryPlugin = function() {
    // Plugin code here
  };
}(jQuery);

If there is a module loader, then factory is registered as the callback for the loader to invoke after loading jQuery. The loaded copy of jQuery is the argument. It's equivalent to

define(['jquery'], function($) {
  $.fn.yourjQueryPlugin = function() {
     // Plugin code here
  };
})

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...