javascript - jQuery selector, contains to equals

Question

I have the folowing selector

    var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
                                            .find("option:contains('LIKE')");

this checks for an option which contains the word 'like' right?

How do i find an option which is exactly with the word 'like'?

Somthing like this:

     var likeComperssionOption = $('select[id*=ComparisionType]').eq(0)
                                            .find("option:equals('LIKE')");

Answer 1

Just select all the options from the select and filter them by text() value:

var likeComperssionOption = $('select[id*=ComparisionType]:first option').filter(function() { return $(this).text() == "LIKE" });