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Hello everyone I am posting a sample code in which I am uploading a file using Ajax JQuery. All thing works fine but I want to read the file content in my php code. So what is the syntax to read it?

    <?php

?>

<!--================================html==================================================-->

<html>
<head>
    <title>AJAX UPLOAD</title>
    <script type="text/javascript" src="jquery-2.0.2.js"></script>
    <script type="text/javascript">
        $(document).ready(function(){
            $('#Button_').click(function(){
                alert("hi");
                var name= document.getElementById('File_');
                 var alpha=name.files[0];
                console.log(alpha.name);
                 var data= new FormData();
                 data.append('file',alpha);
                 $.ajax({
                 url:'process.php',
                 data:data,
                 processData:false,
                 contentType:false,
                 type:'POST',
                 success:function(msg){
                 alert(msg);
                 }
                 });
            });
        });
    </script>
</head>
<body>
    <input type="file" name="File" id="File_"/>
    <input type="button" name="Button" id="Button_" value="UPLOAD">
</body>
</html>

Now I do not know how to read the file data sent via Ajax. So please let me know the code

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1 Answer

The first argument you pass to FormData.append() is the name of the form element that is passed to the server. So data.append('file', alpha) in your case is equivalent to <input type="file" name="file"> - you passed 'file' to append() so 'file' is your input name.

You should find your stuff in $_POST['file'] and $_FILES['file']. Next time try var_dump($_POST); after submit to see the array. :)

Learn about file uploads in php here: http://php.net/manual/en/features.file-upload.php


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