Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
menu search
person
Welcome To Ask or Share your Answers For Others

Categories

The following code displays random database images as well as one specific image (which is what I want). How can I shuffle these results after database query as image ID 11 is always displayed first? I want image ID 11 displayed randomly amongst the others.

Can I use SHUFFLE(). If so where exactly do I put it as at the moment?

Any help would be appreciated as still learning PHP

Thanks.

<?php 

mysql_connect("", "", "") or die(mysql_error()) ; 
mysql_select_db("images") or die(mysql_error()) ;


$photo=mysql_query("SELECT * FROM `profile_images` ORDER BY (ID = 11) DESC, RAND()      
LIMIT 7");


while($get_photo=mysql_fetch_array($photo)){ ?>

<div style="width:300px;">


<img src="<? echo $get_photo['url']; ?>">


</div>

<? } ?>
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
600 views
Welcome To Ask or Share your Answers For Others

1 Answer

You can shuffle them after they are retrieved to php.

$photos = array();
while ($get_photo = mysql_fetch_array($photo))
    $photos[] = $get_photo;

shuffle($photos);

Or you can do it with subqueries:

SELECT A.* FROM (
    SELECT * FROM `profile_images` 
    ORDER BY (ID = 11) DESC, RAND()      
    LIMIT 7
) as A
ORDER BY RAND()

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
thumb_up_alt 0 like thumb_down_alt 0 dislike
Welcome to ShenZhenJia Knowledge Sharing Community for programmer and developer-Open, Learning and Share
...