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I'm using Express and EJS to serve pages. I'm using Bootstrap for the UI, specifically the navbar.

I'd like to add an 'active' class to the current page's <li> item, to show the current page. However, I cannot find how to get the URL from within the EJS code rendering the page.

I found 2 workarounds: I used included passing the page name as a parameter in the route's res.render('myview', {pageName: 'myView'}); - which is not scalable and may cause issues.

The other way, was to use jQuery on the client side to add the 'active' class to the item upon page ready - but that means including this piece of script on every view + some useless client side cycles.

Having used several server side rendering languages before, I feel like I'm missing something. And the online EJS documentation is not that great.

Is there any way to find my current path/url from the EJS code?

Update: I took the top 2 suggestions, and passed the view name as a parameter to the view. I really liked @tandrewnichols' idea to calculate it automatically, but ultimately, it was easier to just copy-paste strings :)

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As far as I know, you can't do what you're asking for unless you modify EJS internally. However, a less bothersome solution would be to pass the URL property of the request on each page invocation, rather than define it per route.

app.get('/url', function (req, res) {
  res.render('view', {
    page: req.url,
    nav: {
      'Page 1': '/page1',
      'Page 2': '/page2',
      'Page 3': '/page3'
    }
  });
});

If you only wanted to get the first part of the URL and match it, then you could just call split('/') on req.url. You could then put a loop inside your template file to create the list for your navigation bar.

<% nav.forEach(function(title) { %>
  <% if (nav[title] == page) { %>
    <li class="active">This part of the navigation bar is active.</li>
  <% } else { %>
    <li>This part of the navigation bar is normal.</li>
  <% } %>
<% }) %>

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