c# - How to Compare SolidColorBrushes?

Question

I am trying to Compare 2 Brushes as you can see in the Picture. I have no Idea why its failing...

Answer 1

They won't be equal because it's doing a reference comparison and they are two different references in the heap with the same properties.

If you want to control object comparisons, you should implement the IEqualtable interface. You can then say how the objects must be compared. In this case however, since SolidColorBrush is a .NET class, we cannot implement IEquatable. There are different options

1) Use an extension method on the SolidColorBrush which compares a brush instance with another. Not a very good solution in this case though.

2) The best bet would proably be to use IEqualityComparer interface. You create a seperate class implementing IEqualityComparer, which will define how to compare 2 different objects. For instance in your example, you may want to compare the SolidColorBrush on Color and Opacity:

public class SolidColorBrushComparer : IEqualityComparer<SolidColorBrush>
{
    public bool Equals(SolidColorBrush x, SolidColorBrush y)
    {
        return x.Color == y.Color && 
            x.Opacity == y.Opacity;
    }

    public int GetHashCode(SolidColorBrush obj)
    {
        return new { C = obj.Color, O = obj.Opacity }.GetHashCode();
    }
}

And then to compare you simply do the following:

SolidColorBrush otherBrush = (SolidColorBrush)(new BrushConverter().ConvertFrom("#FFEFEEEE"));
SolidColorBrush backgroundBrush = (SolidColorBrush)grd.Background;

if(new SolidColorBrushComparer().Equals(backgroundBrush, otherBrush))
{
   // They're equal, Yay!
}